x^2+3x+(9/2)

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Solution for x^2+3x+(9/2) equation: 


x in (-oo:+oo)

x^2+3*x+9/2 = 0

x^2+3*x+9/2 = 0

DELTA = 3^2-(1*4*9/2)

DELTA = -9

DELTA < 0

x belongs to the empty set

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